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【350105】4.4 第2课时 平行线的判定方法2,3

时间:2025-03-06 06:49:02 作者: 字数:1847字

4.4 平行线的判定

2课时 平行线的判定方法2,3


学习目标:

1. <a href="/tags/16/" title="课时" class="c1" target="_blank">课时</a> <a href="/tags/58/" title="平行" class="c1" target="_blank">平行</a> <a href="/tags/74/" title="平行线" class="c1" target="_blank">平行线</a> <a href="/tags/213/" title="方法" class="c1" target="_blank">方法</a> <a href="/tags/868/" title="判定" class="c1" target="_blank">判定</a> 行线的判定定理23

2.能运用性质定理、判定定理进行简单 <a href="/tags/16/" title="课时" class="c1" target="_blank">课时</a> <a href="/tags/58/" title="平行" class="c1" target="_blank">平行</a> <a href="/tags/74/" title="平行线" class="c1" target="_blank">平行线</a> <a href="/tags/213/" title="方法" class="c1" target="_blank">方法</a> <a href="/tags/868/" title="判定" class="c1" target="_blank">判定</a> 的推理和解答相关问题.

重点: <a href="/tags/16/" title="课时" class="c1" target="_blank">课时</a> <a href="/tags/58/" title="平行" class="c1" target="_blank">平行</a> <a href="/tags/74/" title="平行线" class="c1" target="_blank">平行线</a> <a href="/tags/213/" title="方法" class="c1" target="_blank">方法</a> <a href="/tags/868/" title="判定" class="c1" target="_blank">判定</a> 行线的判定定理23

难点:能运用性质定理、判定定理进行简单 <a href="/tags/16/" title="课时" class="c1" target="_blank">课时</a> <a href="/tags/58/" title="平行" class="c1" target="_blank">平行</a> <a href="/tags/74/" title="平行线" class="c1" target="_blank">平行线</a> <a href="/tags/213/" title="方法" class="c1" target="_blank">方法</a> <a href="/tags/868/" title="判定" class="c1" target="_blank">判定</a> 的推理

预习导学——不看不讲

学一学:阅读教材P92-93 的内容

Shape1

知识点一、 <a href="/tags/16/" title="课时" class="c1" target="_blank">课时</a> <a href="/tags/58/" title="平行" class="c1" target="_blank">平行</a> <a href="/tags/74/" title="平行线" class="c1" target="_blank">平行线</a> <a href="/tags/213/" title="方法" class="c1" target="_blank">方法</a> <a href="/tags/868/" title="判定" class="c1" target="_blank">判定</a> 行线的判定定理2



 <a href="/tags/16/" title="课时" class="c1" target="_blank">课时</a> <a href="/tags/58/" title="平行" class="c1" target="_blank">平行</a> <a href="/tags/74/" title="平行线" class="c1" target="_blank">平行线</a> <a href="/tags/213/" title="方法" class="c1" target="_blank">方法</a> <a href="/tags/868/" title="判定" class="c1" target="_blank">判定</a>

填一填:如图 已知∠1=∠2,试证明a∥b

∵∠1=∠2( )

又∠1=∠3( )

∴∠2=∠3( )

( )


【归纳总结】判定定理2 两条直线被第三条直线所截,若内错角相等,则

简单的说:

Shape2

知识点二、 <a href="/tags/16/" title="课时" class="c1" target="_blank">课时</a> <a href="/tags/58/" title="平行" class="c1" target="_blank">平行</a> <a href="/tags/74/" title="平行线" class="c1" target="_blank">平行线</a> <a href="/tags/213/" title="方法" class="c1" target="_blank">方法</a> <a href="/tags/868/" title="判定" class="c1" target="_blank">判定</a> 行线的判定定理3




 <a href="/tags/16/" title="课时" class="c1" target="_blank">课时</a> <a href="/tags/58/" title="平行" class="c1" target="_blank">平行</a> <a href="/tags/74/" title="平行线" class="c1" target="_blank">平行线</a> <a href="/tags/213/" title="方法" class="c1" target="_blank">方法</a> <a href="/tags/868/" title="判定" class="c1" target="_blank">判定</a>

做一做:当∠2+∠41800时,AB∥CD吗?你能说明理由吗?







【归纳总结】判定定理3 两条直线被第三条直线所截,若同旁内角互补,则


简单的说:






【课堂展示】如图AB∥CD, ∠ABC=∠ <a href="/tags/16/" title="课时" class="c1" target="_blank">课时</a> <a href="/tags/58/" title="平行" class="c1" target="_blank">平行</a> <a href="/tags/74/" title="平行线" class="c1" target="_blank">平行线</a> <a href="/tags/213/" title="方法" class="c1" target="_blank">方法</a> <a href="/tags/868/" title="判定" class="c1" target="_blank">判定</a> ADC

 <a href="/tags/16/" title="课时" class="c1" target="_blank">课时</a> <a href="/tags/58/" title="平行" class="c1" target="_blank">平行</a> <a href="/tags/74/" title="平行线" class="c1" target="_blank">平行线</a> <a href="/tags/213/" title="方法" class="c1" target="_blank">方法</a> <a href="/tags/868/" title="判定" class="c1" target="_blank">判定</a> 问:AD∥BC吗?






合作探究——不议不讲

互动探究一:如图,  <a href="/tags/16/" title="课时" class="c1" target="_blank">课时</a> <a href="/tags/58/" title="平行" class="c1" target="_blank">平行</a> <a href="/tags/74/" title="平行线" class="c1" target="_blank">平行线</a> <a href="/tags/213/" title="方法" class="c1" target="_blank">方法</a> <a href="/tags/868/" title="判定" class="c1" target="_blank">判定</a> AB∥CD,∠A+∠AEF=180°, <a href="/tags/16/" title="课时" class="c1" target="_blank">课时</a> <a href="/tags/58/" title="平行" class="c1" target="_blank">平行</a> <a href="/tags/74/" title="平行线" class="c1" target="_blank">平行线</a> <a href="/tags/213/" title="方法" class="c1" target="_blank">方法</a> <a href="/tags/868/" title="判定" class="c1" target="_blank">判定</a> 那么CDFE平行吗?为什么?


 <a href="/tags/16/" title="课时" class="c1" target="_blank">课时</a> <a href="/tags/58/" title="平行" class="c1" target="_blank">平行</a> <a href="/tags/74/" title="平行线" class="c1" target="_blank">平行线</a> <a href="/tags/213/" title="方法" class="c1" target="_blank">方法</a> <a href="/tags/868/" title="判定" class="c1" target="_blank">判定</a>












互动探究二:如图∠1=∠2,∠A=∠F,试说明∠D=∠C

 <a href="/tags/16/" title="课时" class="c1" target="_blank">课时</a> <a href="/tags/58/" title="平行" class="c1" target="_blank">平行</a> <a href="/tags/74/" title="平行线" class="c1" target="_blank">平行线</a> <a href="/tags/213/" title="方法" class="c1" target="_blank">方法</a> <a href="/tags/868/" title="判定" class="c1" target="_blank">判定</a>












【当堂检测】P94 练习1题,2







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