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【329852】7.4 平行线的性质 同步练习3

时间:2025-02-05 18:12:13 作者: 字数:3999字


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7.4 平行线的性质

一、选择题

1、若两条平行线被第三条直线所截,则下列说法错误的是( )

A、一对同位角的平分线互相平行 B、一对内错角的平分线互相平行

C、一对同旁内角的平分线互相平行 D、一对同旁内角的平分线互相垂直

2、如图1,直线AB∥CDEF⊥ABE,交CD F,直线MNABMCDNEFO,则直线ABCD之间的距离是哪个线段的长( )

AMN BEF COE DOF

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1) (2) (3) (4

3、如图2AB∥CD,∠α=( )

A50° B80° C85° D95°

4、已知∠A50°,∠A的两边分别平行于∠B的两边,则∠B=( )

A50° B130° C100° D50°130°

5、如图3AB∥CDADBC相交于O,∠BAD35°,∠BOD76°,则∠C的度数是( )

A31° B35° C41° D76°

6、如图4OP∥QR∥ST,则下列等式中正确的是( )

A、∠1+∠2-∠390° B、∠2+∠3-∠1180°

C、∠1-∠2+∠3180° D、∠1+∠2+∠3180°

二、填空题

7、如图5AB∥CD,∠B42°,∠235°,则∠1_____,∠A______,∠ACB______,∠BCD______.

8、如图6AB∥CD,∠EGD50°,∠AEM30°,则∠1_________°

9、如图7,若AB∥DEBC∥FE,∠E+∠B__________°

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5) (6) (7

10、如图8DH∥EG∥BCDC∥EF,那么与∠1相等的角共有______.

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8) (9) (10

11、如图9,∠ABC和∠ACB的平分线BOCO相交于点OEF过点O,且EF∥BC,若∠BOC130°,∠ABC∶∠ACB3∶2,则∠AEF_______,∠EFC_______.

12、如图10AB之间是一座山,一条铁路要通过AB两地,在A地测得铁路的走向是北偏东68°20′,如果AB两地同时开工,那么在B地按_________方向施工,才能使铁路在山腹中准确接通.

三、解答题

13、如图,已知∠B=∠CAE∥BC,说明AE平分∠CAD.

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14、如图,已知DE∥BCCD是∠ACB的平分线,∠B70°,∠ACB50°,求∠EDC和∠BDC的度数.

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15、如图,直线ADABCD相交于AD两点,ECBFABCD相交于ECBF,如果∠1=∠2,∠B=∠C.说明∠A=∠D.

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16、如图,已知AB∥CD,分别探究下面四个图形中∠APC和∠PAB、∠PCD的关系,并从所得的四个关系中任选一个加以说明,证明所探究的结论的正确性.

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结论(1__________________________;(2_______________________

3_________________________;(4_________________________

选择结论________,说明理由是什么.



四、拓展探究(不计入总分)

17、如图,AB∥CDEF⊥ABO ,∠2135°,求∠1的度数.

下面提供三个思路:(1)过FFH∥AB,(2)延长EFCDI;(3)延长GFABK.请你利用三个思路中的两个思路,求∠1的度数.

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参考答案

1C 2B 3C 4D 5C 6B

742° 35° 103° 138° 8100 9180 105

1160° 40° 12、南偏西68°20′

13、∵AE∥BC,∴∠EAC=∠C,∠DAE=∠B

∵∠B=∠C,∴∠DAE=∠EAC,∴AE平分∠CAD

14、∠EDC25°,∠BDC85°

15、∵∠2=∠AGB,∠1=∠2,∴∠1=∠AGB,∴CE∥BF

∴∠B=∠AEC,∵∠B=∠C,∴∠C=∠AEC,∴AB∥CD,∴∠A=∠D

16、结论:(1)∠P+∠A+∠C180°;(2)∠P=∠A+∠C

3)∠C-∠A=∠P;(4)∠A-∠C=∠P

理由:提示过点PAB的平行线

17135°