当前位置:首页 > 八年级 > 数学试卷

【323307】2023八年级数学上册 第11章 平面直角坐标系测试题 (新版)沪科版

时间:2025-01-15 20:30:52 作者: 字数:5569字
简介:


11章 平面直角坐标系检测题

一、选择题

 <a href="/tags/4/" title="测试" class="c1" target="_blank">测试</a> <a href="/tags/51/" title="试题" class="c1" target="_blank">试题</a> <a href="/tags/55/" title="数学" class="c1" target="_blank">数学</a> <a href="/tags/180/" title="直角" class="c1" target="_blank">直角</a> <a href="/tags/453/" title="平面" class="c1" target="_blank">平面</a> <a href="/tags/873/" title="直角坐标" class="c1" target="_blank">直角坐标</a> 1.B 解析:因为点 <a href="/tags/4/" title="测试" class="c1" target="_blank">测试</a> <a href="/tags/51/" title="试题" class="c1" target="_blank">试题</a> <a href="/tags/55/" title="数学" class="c1" target="_blank">数学</a> <a href="/tags/180/" title="直角" class="c1" target="_blank">直角</a> <a href="/tags/453/" title="平面" class="c1" target="_blank">平面</a> <a href="/tags/873/" title="直角坐标" class="c1" target="_blank">直角坐标</a> 在第三象限,所以 <a href="/tags/4/" title="测试" class="c1" target="_blank">测试</a> <a href="/tags/51/" title="试题" class="c1" target="_blank">试题</a> <a href="/tags/55/" title="数学" class="c1" target="_blank">数学</a> <a href="/tags/180/" title="直角" class="c1" target="_blank">直角</a> <a href="/tags/453/" title="平面" class="c1" target="_blank">平面</a> <a href="/tags/873/" title="直角坐标" class="c1" target="_blank">直角坐标</a>  <a href="/tags/4/" title="测试" class="c1" target="_blank">测试</a> <a href="/tags/51/" title="试题" class="c1" target="_blank">试题</a> <a href="/tags/55/" title="数学" class="c1" target="_blank">数学</a> <a href="/tags/180/" title="直角" class="c1" target="_blank">直角</a> <a href="/tags/453/" title="平面" class="c1" target="_blank">平面</a> <a href="/tags/873/" title="直角坐标" class="c1" target="_blank">直角坐标</a> ,所以 <a href="/tags/4/" title="测试" class="c1" target="_blank">测试</a> <a href="/tags/51/" title="试题" class="c1" target="_blank">试题</a> <a href="/tags/55/" title="数学" class="c1" target="_blank">数学</a> <a href="/tags/180/" title="直角" class="c1" target="_blank">直角</a> <a href="/tags/453/" title="平面" class="c1" target="_blank">平面</a> <a href="/tags/873/" title="直角坐标" class="c1" target="_blank">直角坐标</a>

所以 <a href="/tags/4/" title="测试" class="c1" target="_blank">测试</a> <a href="/tags/51/" title="试题" class="c1" target="_blank">试题</a> <a href="/tags/55/" title="数学" class="c1" target="_blank">数学</a> <a href="/tags/180/" title="直角" class="c1" target="_blank">直角</a> <a href="/tags/453/" title="平面" class="c1" target="_blank">平面</a> <a href="/tags/873/" title="直角坐标" class="c1" target="_blank">直角坐标</a> ,所以点 <a href="/tags/4/" title="测试" class="c1" target="_blank">测试</a> <a href="/tags/51/" title="试题" class="c1" target="_blank">试题</a> <a href="/tags/55/" title="数学" class="c1" target="_blank">数学</a> <a href="/tags/180/" title="直角" class="c1" target="_blank">直角</a> <a href="/tags/453/" title="平面" class="c1" target="_blank">平面</a> <a href="/tags/873/" title="直角坐标" class="c1" target="_blank">直角坐标</a> 在第二象限,故选B.

2.B 解析:由题意知点P在第四象限,所以.

3.D 解析:∵ 点 <a href="/tags/4/" title="测试" class="c1" target="_blank">测试</a> <a href="/tags/51/" title="试题" class="c1" target="_blank">试题</a> <a href="/tags/55/" title="数学" class="c1" target="_blank">数学</a> <a href="/tags/180/" title="直角" class="c1" target="_blank">直角</a> <a href="/tags/453/" title="平面" class="c1" target="_blank">平面</a> <a href="/tags/873/" title="直角坐标" class="c1" target="_blank">直角坐标</a> 在轴上,∴ 纵坐标是0,即.又∵ 点位于原点的左侧,∴ 横坐标小于0,即,∴ ,故选D

4.D 解析: 在平面直角坐标系中,一个图案上各个点的横坐标和纵坐标分别正数,图案向右平移了个单位,并且向上平移了个单位.

5.D 解析:过点作⊥轴于点,则点的坐标为(30.

因为点到轴的距离为4,所以.又因为,

所以由勾股定理得,

所以点的坐标为(60)或(00),故选D.

6.A 解析:设点到轴的距离为,则.

因为,所以,故选A.

7. <a href="/tags/4/" title="测试" class="c1" target="_blank">测试</a> <a href="/tags/51/" title="试题" class="c1" target="_blank">试题</a> <a href="/tags/55/" title="数学" class="c1" target="_blank">数学</a> <a href="/tags/180/" title="直角" class="c1" target="_blank">直角</a> <a href="/tags/453/" title="平面" class="c1" target="_blank">平面</a> <a href="/tags/873/" title="直角坐标" class="c1" target="_blank">直角坐标</a> D 解析:因为点P()的坐标满足 <a href="/tags/4/" title="测试" class="c1" target="_blank">测试</a> <a href="/tags/51/" title="试题" class="c1" target="_blank">试题</a> <a href="/tags/55/" title="数学" class="c1" target="_blank">数学</a> <a href="/tags/180/" title="直角" class="c1" target="_blank">直角</a> <a href="/tags/453/" title="平面" class="c1" target="_blank">平面</a> <a href="/tags/873/" title="直角坐标" class="c1" target="_blank">直角坐标</a> =0,所以所以点P在轴上或在轴上,故选D.

8.D 解析:将点A向左平移2个单位,即横坐标减2,纵坐标不变,所以点B的坐标为(0,1),故选D.

9.D 解析:∵ 点距离轴5个单位,∴ 点的纵坐标是±5.

又∵ 点在轴的上侧,∴ 点的纵坐标是5.

点距离轴3个单位,即横坐标是±3

点的坐标为(-35)或(35),故选D

10.B 解析:已知 <a href="/tags/4/" title="测试" class="c1" target="_blank">测试</a> <a href="/tags/51/" title="试题" class="c1" target="_blank">试题</a> <a href="/tags/55/" title="数学" class="c1" target="_blank">数学</a> <a href="/tags/180/" title="直角" class="c1" target="_blank">直角</a> <a href="/tags/453/" title="平面" class="c1" target="_blank">平面</a> <a href="/tags/873/" title="直角坐标" class="c1" target="_blank">直角坐标</a> 两点的坐标分别是(20),(00),则可知 <a href="/tags/4/" title="测试" class="c1" target="_blank">测试</a> <a href="/tags/51/" title="试题" class="c1" target="_blank">试题</a> <a href="/tags/55/" title="数学" class="c1" target="_blank">数学</a> <a href="/tags/180/" title="直角" class="c1" target="_blank">直角</a> <a href="/tags/453/" title="平面" class="c1" target="_blank">平面</a> <a href="/tags/873/" title="直角坐标" class="c1" target="_blank">直角坐标</a> 两点的横坐标一定是1,且 <a href="/tags/4/" title="测试" class="c1" target="_blank">测试</a> <a href="/tags/51/" title="试题" class="c1" target="_blank">试题</a> <a href="/tags/55/" title="数学" class="c1" target="_blank">数学</a> <a href="/tags/180/" title="直角" class="c1" target="_blank">直角</a> <a href="/tags/453/" title="平面" class="c1" target="_blank">平面</a> <a href="/tags/873/" title="直角坐标" class="c1" target="_blank">直角坐标</a> 两点关于轴对称,纵坐标互为相反数.设点的坐标为(1,),则有,解得,所以点的坐标为(11),点的坐标为( <a href="/tags/4/" title="测试" class="c1" target="_blank">测试</a> <a href="/tags/51/" title="试题" class="c1" target="_blank">试题</a> <a href="/tags/55/" title="数学" class="c1" target="_blank">数学</a> <a href="/tags/180/" title="直角" class="c1" target="_blank">直角</a> <a href="/tags/453/" title="平面" class="c1" target="_blank">平面</a> <a href="/tags/873/" title="直角坐标" class="c1" target="_blank">直角坐标</a> 1,-1),故选B.

11.C “帅”位于点 <a href="/tags/4/" title="测试" class="c1" target="_blank">测试</a> <a href="/tags/51/" title="试题" class="c1" target="_blank">试题</a> <a href="/tags/55/" title="数学" class="c1" target="_blank">数学</a> <a href="/tags/180/" title="直角" class="c1" target="_blank">直角</a> <a href="/tags/453/" title="平面" class="c1" target="_blank">平面</a> <a href="/tags/873/" title="直角坐标" class="c1" target="_blank">直角坐标</a> “馬”位 <a href="/tags/4/" title="测试" class="c1" target="_blank">测试</a> <a href="/tags/51/" title="试题" class="c1" target="_blank">试题</a> <a href="/tags/55/" title="数学" class="c1" target="_blank">数学</a> <a href="/tags/180/" title="直角" class="c1" target="_blank">直角</a> <a href="/tags/453/" title="平面" class="c1" target="_blank">平面</a> <a href="/tags/873/" title="直角坐标" class="c1" target="_blank">直角坐标</a> 于点 <a href="/tags/4/" title="测试" class="c1" target="_blank">测试</a> <a href="/tags/51/" title="试题" class="c1" target="_blank">试题</a> <a href="/tags/55/" title="数学" class="c1" target="_blank">数学</a> <a href="/tags/180/" title="直角" class="c1" target="_blank">直角</a> <a href="/tags/453/" title="平面" class="c1" target="_blank">平面</a> <a href="/tags/873/" title="直角坐标" class="c1" target="_blank">直角坐标</a> ,可得出原点在棋子的位置,所以“兵”位于点 <a href="/tags/4/" title="测试" class="c1" target="_blank">测试</a> <a href="/tags/51/" title="试题" class="c1" target="_blank">试题</a> <a href="/tags/55/" title="数学" class="c1" target="_blank">数学</a> <a href="/tags/180/" title="直角" class="c1" target="_blank">直角</a> <a href="/tags/453/" title="平面" class="c1" target="_blank">平面</a> <a href="/tags/873/" title="直角坐标" class="c1" target="_blank">直角坐标</a> ,故选C

12.D 解析:矩形的边长为42,因为物体乙的速度是物体甲的2倍,且运动时间相同,所以物体甲与物体乙的路程比为 <a href="/tags/4/" title="测试" class="c1" target="_blank">测试</a> <a href="/tags/51/" title="试题" class="c1" target="_blank">试题</a> <a href="/tags/55/" title="数学" class="c1" target="_blank">数学</a> <a href="/tags/180/" title="直角" class="c1" target="_blank">直角</a> <a href="/tags/453/" title="平面" class="c1" target="_blank">平面</a> <a href="/tags/873/" title="直角坐标" class="c1" target="_blank">直角坐标</a> ,由题意知:

第一次相遇时,物体甲与物体乙行驶的路程和为12×1,物体甲行驶的路程为12× <a href="/tags/4/" title="测试" class="c1" target="_blank">测试</a> <a href="/tags/51/" title="试题" class="c1" target="_blank">试题</a> <a href="/tags/55/" title="数学" class="c1" target="_blank">数学</a> <a href="/tags/180/" title="直角" class="c1" target="_blank">直角</a> <a href="/tags/453/" title="平面" class="c1" target="_blank">平面</a> <a href="/tags/873/" title="直角坐标" class="c1" target="_blank">直角坐标</a> =4,物体乙行驶的路程为12× <a href="/tags/4/" title="测试" class="c1" target="_blank">测试</a> <a href="/tags/51/" title="试题" class="c1" target="_blank">试题</a> <a href="/tags/55/" title="数学" class="c1" target="_blank">数学</a> <a href="/tags/180/" title="直角" class="c1" target="_blank">直角</a> <a href="/tags/453/" title="平面" class="c1" target="_blank">平面</a> <a href="/tags/873/" title="直角坐标" class="c1" target="_blank">直角坐标</a> =8,在BC边相遇;

第二次相遇时,物体甲与物体乙行驶的路程和为12×2,物体甲行驶的路程为12×2× <a href="/tags/4/" title="测试" class="c1" target="_blank">测试</a> <a href="/tags/51/" title="试题" class="c1" target="_blank">试题</a> <a href="/tags/55/" title="数学" class="c1" target="_blank">数学</a> <a href="/tags/180/" title="直角" class="c1" target="_blank">直角</a> <a href="/tags/453/" title="平面" class="c1" target="_blank">平面</a> <a href="/tags/873/" title="直角坐标" class="c1" target="_blank">直角坐标</a> =8,物体乙行 <a href="/tags/4/" title="测试" class="c1" target="_blank">测试</a> <a href="/tags/51/" title="试题" class="c1" target="_blank">试题</a> <a href="/tags/55/" title="数学" class="c1" target="_blank">数学</a> <a href="/tags/180/" title="直角" class="c1" target="_blank">直角</a> <a href="/tags/453/" title="平面" class="c1" target="_blank">平面</a> <a href="/tags/873/" title="直角坐标" class="c1" target="_blank">直角坐标</a> 驶的路程为12×2× <a href="/tags/4/" title="测试" class="c1" target="_blank">测试</a> <a href="/tags/51/" title="试题" class="c1" target="_blank">试题</a> <a href="/tags/55/" title="数学" class="c1" target="_blank">数学</a> <a href="/tags/180/" title="直角" class="c1" target="_blank">直角</a> <a href="/tags/453/" title="平面" class="c1" target="_blank">平面</a> <a href="/tags/873/" title="直角坐标" class="c1" target="_blank">直角坐标</a> =16,在 <a href="/tags/4/" title="测试" class="c1" target="_blank">测试</a> <a href="/tags/51/" title="试题" class="c1" target="_blank">试题</a> <a href="/tags/55/" title="数学" class="c1" target="_blank">数学</a> <a href="/tags/180/" title="直角" class="c1" target="_blank">直角</a> <a href="/tags/453/" title="平面" class="c1" target="_blank">平面</a> <a href="/tags/873/" title="直角坐标" class="c1" target="_blank">直角坐标</a> 边相遇;

第三次相遇时,物体甲与物体乙行驶的路程和为12×3,物体甲行驶的路程为12×3× <a href="/tags/4/" title="测试" class="c1" target="_blank">测试</a> <a href="/tags/51/" title="试题" class="c1" target="_blank">试题</a> <a href="/tags/55/" title="数学" class="c1" target="_blank">数学</a> <a href="/tags/180/" title="直角" class="c1" target="_blank">直角</a> <a href="/tags/453/" title="平面" class="c1" target="_blank">平面</a> <a href="/tags/873/" title="直角坐标" class="c1" target="_blank">直角坐标</a> =12,物体乙行驶的路程为12×3× <a href="/tags/4/" title="测试" class="c1" target="_blank">测试</a> <a href="/tags/51/" title="试题" class="c1" target="_blank">试题</a> <a href="/tags/55/" title="数学" class="c1" target="_blank">数学</a> <a href="/tags/180/" title="直角" class="c1" target="_blank">直角</a> <a href="/tags/453/" title="平面" class="c1" target="_blank">平面</a> <a href="/tags/873/" title="直角坐标" class="c1" target="_blank">直角坐标</a> =24,在 <a href="/tags/4/" title="测试" class="c1" target="_blank">测试</a> <a href="/tags/51/" title="试题" class="c1" target="_blank">试题</a> <a href="/tags/55/" title="数学" class="c1" target="_blank">数学</a> <a href="/tags/180/" title="直角" class="c1" target="_blank">直角</a> <a href="/tags/453/" title="平面" class="c1" target="_blank">平面</a> <a href="/tags/873/" title="直角坐标" class="c1" target="_blank">直角坐标</a> 点相遇,此时物体甲、乙回到原出发点.即每相遇三次,两物体回到出发点.

因为2 012÷3=670……2

故两个物体运动后的第2012次相遇地点是第二次相遇地点.

由上述可知第二次相遇地点的坐标为 <a href="/tags/4/" title="测试" class="c1" target="_blank">测试</a> <a href="/tags/51/" title="试题" class="c1" target="_blank">试题</a> <a href="/tags/55/" title="数学" class="c1" target="_blank">数学</a> <a href="/tags/180/" title="直角" class="c1" target="_blank">直角</a> <a href="/tags/453/" title="平面" class="c1" target="_blank">平面</a> <a href="/tags/873/" title="直角坐标" class="c1" target="_blank">直角坐标</a> ,故选D

填空

13. 解析:因为点是第二象限的点,所以 <a href="/tags/4/" title="测试" class="c1" target="_blank">测试</a> <a href="/tags/51/" title="试题" class="c1" target="_blank">试题</a> <a href="/tags/55/" title="数学" class="c1" target="_blank">数学</a> <a href="/tags/180/" title="直角" class="c1" target="_blank">直角</a> <a href="/tags/453/" title="平面" class="c1" target="_blank">平面</a> <a href="/tags/873/" title="直角坐标" class="c1" target="_blank">直角坐标</a> 解得.

14.34) 解析:关于 <a href="/tags/4/" title="测试" class="c1" target="_blank">测试</a> <a href="/tags/51/" title="试题" class="c1" target="_blank">试题</a> <a href="/tags/55/" title="数学" class="c1" target="_blank">数学</a> <a href="/tags/180/" title="直角" class="c1" target="_blank">直角</a> <a href="/tags/453/" title="平面" class="c1" target="_blank">平面</a> <a href="/tags/873/" title="直角坐标" class="c1" target="_blank">直角坐标</a> 轴对称的两点的纵坐标相等,横坐标互为相反数

15.32解析:一只蚂蚁由点(00)先向上爬4个单位后坐标变为(04),再向右爬3个单位后坐标变为(34),再向下爬2个单位后坐标变为(32),故此时它所在位置的坐标为(32.

16.轴 解析:∵ <a href="/tags/4/" title="测试" class="c1" target="_blank">测试</a> <a href="/tags/51/" title="试题" class="c1" target="_blank">试题</a> <a href="/tags/55/" title="数学" class="c1" target="_blank">数学</a> <a href="/tags/180/" title="直角" class="c1" target="_blank">直角</a> <a href="/tags/453/" title="平面" class="c1" target="_blank">平面</a> <a href="/tags/873/" title="直角坐标" class="c1" target="_blank">直角坐标</a> ,∴ ,,∴ 两点关于轴对称.

17. <a href="/tags/4/" title="测试" class="c1" target="_blank">测试</a> <a href="/tags/51/" title="试题" class="c1" target="_blank">试题</a> <a href="/tags/55/" title="数学" class="c1" target="_blank">数学</a> <a href="/tags/180/" title="直角" class="c1" target="_blank">直角</a> <a href="/tags/453/" title="平面" class="c1" target="_blank">平面</a> <a href="/tags/873/" title="直角坐标" class="c1" target="_blank">直角坐标</a>  <a href="/tags/4/" title="测试" class="c1" target="_blank">测试</a> <a href="/tags/51/" title="试题" class="c1" target="_blank">试题</a> <a href="/tags/55/" title="数学" class="c1" target="_blank">数学</a> <a href="/tags/180/" title="直角" class="c1" target="_blank">直角</a> <a href="/tags/453/" title="平面" class="c1" target="_blank">平面</a> <a href="/tags/873/" title="直角坐标" class="c1" target="_blank">直角坐标</a> 不变 向上平移了个单位

18.向下平移了1个单位 向左平移了1个单位

19. <a href="/tags/4/" title="测试" class="c1" target="_blank">测试</a> <a href="/tags/51/" title="试题" class="c1" target="_blank">试题</a> <a href="/tags/55/" title="数学" class="c1" target="_blank">数学</a> <a href="/tags/180/" title="直角" class="c1" target="_blank">直角</a> <a href="/tags/453/" title="平面" class="c1" target="_blank">平面</a> <a href="/tags/873/" title="直角坐标" class="c1" target="_blank">直角坐标</a> 解析:因为∥ABC <a href="/tags/4/" title="测试" class="c1" target="_blank">测试</a> <a href="/tags/51/" title="试题" class="c1" target="_blank">试题</a> <a href="/tags/55/" title="数学" class="c1" target="_blank">数学</a> <a href="/tags/180/" title="直角" class="c1" target="_blank">直角</a> <a href="/tags/453/" title="平面" class="c1" target="_blank">平面</a> <a href="/tags/873/" title="直角坐标" class="c1" target="_blank">直角坐标</a> D=AB

所以CD=3,点C的横坐标为3,纵坐标为1.所以点C的坐标为 <a href="/tags/4/" title="测试" class="c1" target="_blank">测试</a> <a href="/tags/51/" title="试题" class="c1" target="_blank">试题</a> <a href="/tags/55/" title="数学" class="c1" target="_blank">数学</a> <a href="/tags/180/" title="直角" class="c1" target="_blank">直角</a> <a href="/tags/453/" title="平面" class="c1" target="_blank">平面</a> <a href="/tags/873/" title="直角坐标" class="c1" target="_blank">直角坐标</a>

20.04) 解析:∵ 指令为 <a href="/tags/4/" title="测试" class="c1" target="_blank">测试</a> <a href="/tags/51/" title="试题" class="c1" target="_blank">试题</a> <a href="/tags/55/" title="数学" class="c1" target="_blank">数学</a> <a href="/tags/180/" title="直角" class="c1" target="_blank">直角</a> <a href="/tags/453/" title="平面" class="c1" target="_blank">平面</a> <a href="/tags/873/" title="直角坐标" class="c1" target="_blank">直角坐标</a> ,∴ 机器人应逆时针旋转90°,再朝其面对的方向走 <a href="/tags/4/" title="测试" class="c1" target="_blank">测试</a> <a href="/tags/51/" title="试题" class="c1" target="_blank">试题</a> <a href="/tags/55/" title="数学" class="c1" target="_blank">数学</a> <a href="/tags/180/" title="直角" class="c1" target="_blank">直角</a> <a href="/tags/453/" title="平面" class="c1" target="_blank">平面</a> <a href="/tags/873/" title="直角坐标" class="c1" target="_blank">直角坐标</a> 个单位.∵ 机器人在直角坐标系的坐标原点,且面对轴正方向,∴ 机器人旋转后将面对轴 <a href="/tags/4/" title="测试" class="c1" target="_blank">测试</a> <a href="/tags/51/" title="试题" class="c1" target="_blank">试题</a> <a href="/tags/55/" title="数学" class="c1" target="_blank">数学</a> <a href="/tags/180/" title="直角" class="c1" target="_blank">直角</a> <a href="/tags/453/" title="平面" class="c1" target="_blank">平面</a> <a href="/tags/873/" title="直角坐标" class="c1" target="_blank">直角坐标</a> 的正方向,沿轴正方向走4个单位,∴ 机器人应移动到点(04).

解答

21.解:设△A1B1C1三个顶点的坐标分别为 <a href="/tags/4/" title="测试" class="c1" target="_blank">测试</a> <a href="/tags/51/" title="试题" class="c1" target="_blank">试题</a> <a href="/tags/55/" title="数学" class="c1" target="_blank">数学</a> <a href="/tags/180/" title="直角" class="c1" target="_blank">直角</a> <a href="/tags/453/" title="平面" class="c1" target="_blank">平面</a> <a href="/tags/873/" title="直角坐标" class="c1" target="_blank">直角坐标</a> ,

将三个顶点分别向右平移4个单位,再向下平移3个单位后三个顶点的坐标分别为,

由题意可得=2 <a href="/tags/4/" title="测试" class="c1" target="_blank">测试</a> <a href="/tags/51/" title="试题" class="c1" target="_blank">试题</a> <a href="/tags/55/" title="数学" class="c1" target="_blank">数学</a> <a href="/tags/180/" title="直角" class="c1" target="_blank">直角</a> <a href="/tags/453/" title="平面" class="c1" target="_blank">平面</a> <a href="/tags/873/" title="直角坐标" class="c1" target="_blank">直角坐标</a>

 <a href="/tags/4/" title="测试" class="c1" target="_blank">测试</a> <a href="/tags/51/" title="试题" class="c1" target="_blank">试题</a> <a href="/tags/55/" title="数学" class="c1" target="_blank">数学</a> <a href="/tags/180/" title="直角" class="c1" target="_blank">直角</a> <a href="/tags/453/" title="平面" class="c1" target="_blank">平面</a> <a href="/tags/873/" title="直角坐标" class="c1" target="_blank">直角坐标</a> 所以 <a href="/tags/4/" title="测试" class="c1" target="_blank">测试</a> <a href="/tags/51/" title="试题" class="c1" target="_blank">试题</a> <a href="/tags/55/" title="数学" class="c1" target="_blank">数学</a> <a href="/tags/180/" title="直角" class="c1" target="_blank">直角</a> <a href="/tags/453/" title="平面" class="c1" target="_blank">平面</a> <a href="/tags/873/" title="直角坐标" class="c1" target="_blank">直角坐标</a>  <a href="/tags/4/" title="测试" class="c1" target="_blank">测试</a> <a href="/tags/51/" title="试题" class="c1" target="_blank">试题</a> <a href="/tags/55/" title="数学" class="c1" target="_blank">数学</a> <a href="/tags/180/" title="直角" class="c1" target="_blank">直角</a> <a href="/tags/453/" title="平面" class="c1" target="_blank">平面</a> <a href="/tags/873/" title="直角坐标" class="c1" target="_blank">直角坐标</a> .

22.解:(1)将线段 <a href="/tags/4/" title="测试" class="c1" target="_blank">测试</a> <a href="/tags/51/" title="试题" class="c1" target="_blank">试题</a> <a href="/tags/55/" title="数学" class="c1" target="_blank">数学</a> <a href="/tags/180/" title="直角" class="c1" target="_blank">直角</a> <a href="/tags/453/" title="平面" class="c1" target="_blank">平面</a> <a href="/tags/873/" title="直角坐标" class="c1" target="_blank">直角坐标</a> 先向右平移3个小格(向下平移4个小格),再向下平移4个小格(向右平移3个小格),得到线段 <a href="/tags/4/" title="测试" class="c1" target="_blank">测试</a> <a href="/tags/51/" title="试题" class="c1" target="_blank">试题</a> <a href="/tags/55/" title="数学" class="c1" target="_blank">数学</a> <a href="/tags/180/" title="直角" class="c1" target="_blank">直角</a> <a href="/tags/453/" title="平面" class="c1" target="_blank">平面</a> <a href="/tags/873/" title="直角坐标" class="c1" target="_blank">直角坐标</a> .

 <a href="/tags/4/" title="测试" class="c1" target="_blank">测试</a> <a href="/tags/51/" title="试题" class="c1" target="_blank">试题</a> <a href="/tags/55/" title="数学" class="c1" target="_blank">数学</a> <a href="/tags/180/" title="直角" class="c1" target="_blank">直角</a> <a href="/tags/453/" title="平面" class="c1" target="_blank">平面</a> <a href="/tags/873/" title="直角坐标" class="c1" target="_blank">直角坐标</a> 2)将线段 <a href="/tags/4/" title="测试" class="c1" target="_blank">测试</a> <a href="/tags/51/" title="试题" class="c1" target="_blank">试题</a> <a href="/tags/55/" title="数学" class="c1" target="_blank">数学</a> <a href="/tags/180/" title="直角" class="c1" target="_blank">直角</a> <a href="/tags/453/" title="平面" class="c1" target="_blank">平面</a> <a href="/tags/873/" title="直角坐标" class="c1" target="_blank">直角坐标</a> 先向左平 <a href="/tags/4/" title="测试" class="c1" target="_blank">测试</a> <a href="/tags/51/" title="试题" class="c1" target="_blank">试题</a> <a href="/tags/55/" title="数学" class="c1" target="_blank">数学</a> <a href="/tags/180/" title="直角" class="c1" target="_blank">直角</a> <a href="/tags/453/" title="平面" class="c1" target="_blank">平面</a> <a href="/tags/873/" title="直角坐标" class="c1" target="_blank">直角坐标</a>3个小格(向下平移1个小格),再向下平移1个小格(向左平移3个小格),得到线段 <a href="/tags/4/" title="测试" class="c1" target="_blank">测试</a> <a href="/tags/51/" title="试题" class="c1" target="_blank">试题</a> <a href="/tags/55/" title="数学" class="c1" target="_blank">数学</a> <a href="/tags/180/" title="直角" class="c1" target="_blank">直角</a> <a href="/tags/453/" title="平面" class="c1" target="_blank">平面</a> <a href="/tags/873/" title="直角坐标" class="c1" target="_blank">直角坐标</a>

23.解:(1)因为(03)和(33)的纵坐标相同,

因而 <a href="/tags/4/" title="测试" class="c1" target="_blank">测试</a> <a href="/tags/51/" title="试题" class="c1" target="_blank">试题</a> <a href="/tags/55/" title="数学" class="c1" target="_blank">数学</a> <a href="/tags/180/" title="直角" class="c1" target="_blank">直角</a> <a href="/tags/453/" title="平面" class="c1" target="_blank">平面</a> <a href="/tags/873/" title="直角坐标" class="c1" target="_blank">直角坐标</a> ,故四边形是梯形.作出图形如图所示.

2)因为,,高,

故梯形的面积是 <a href="/tags/4/" title="测试" class="c1" target="_blank">测试</a> <a href="/tags/51/" title="试题" class="c1" target="_blank">试题</a> <a href="/tags/55/" title="数学" class="c1" target="_blank">数学</a> <a href="/tags/180/" title="直角" class="c1" target="_blank">直角</a> <a href="/tags/453/" title="平面" class="c1" target="_blank">平面</a> <a href="/tags/873/" title="直角坐标" class="c1" target="_blank">直角坐标</a>

3)在Rt△中,根据勾股定理得,

同理可得,故梯形的周长是.

DrawObject1 DrawObject2











24.解:路程相等.

走法一:;

走法二:.

答案不唯一.

25.解:(1B11)移动到点D34)处的平移规律可得C13,如图.

2向右平移2个单位再向上平移3个单位即可得到CD

26.分析:(1)根据坐标的确定方法,读出各点的横、纵坐标,即可得出 <a href="/tags/4/" title="测试" class="c1" target="_blank">测试</a> <a href="/tags/51/" title="试题" class="c1" target="_blank">试题</a> <a href="/tags/55/" title="数学" class="c1" target="_blank">数学</a> <a href="/tags/180/" title="直角" class="c1" target="_blank">直角</a> <a href="/tags/453/" title="平面" class="c1" target="_blank">平面</a> <a href="/tags/873/" title="直角坐标" class="c1" target="_blank">直角坐标</a> 各个顶点的坐标;
2)根据平移中点的变化规律:横坐标右移加,左移减,纵坐标上移加,下移减,可得

不能由③通过平移得到;
3)根据对称性,即可得到三角形①、②的顶 <a href="/tags/4/" title="测试" class="c1" target="_blank">测试</a> <a href="/tags/51/" title="试题" class="c1" target="_blank">试题</a> <a href="/tags/55/" title="数学" class="c1" target="_blank">数学</a> <a href="/tags/180/" title="直角" class="c1" target="_blank">直角</a> <a href="/tags/453/" title="平面" class="c1" target="_blank">平面</a> <a href="/tags/873/" title="直角坐标" class="c1" target="_blank">直角坐标</a> 点坐标.

解:(1)(-1-1),(-4-4),(-3-5.

2)不能,下面两个点向右平移了5个单位,上面一个点向右平移了4个单位.

3)三角形②的顶点坐标为 <a href="/tags/4/" title="测试" class="c1" target="_blank">测试</a> <a href="/tags/51/" title="试题" class="c1" target="_blank">试题</a> <a href="/tags/55/" title="数学" class="c1" target="_blank">数学</a> <a href="/tags/180/" title="直角" class="c1" target="_blank">直角</a> <a href="/tags/453/" title="平面" class="c1" target="_blank">平面</a> <a href="/tags/873/" title="直角坐标" class="c1" target="_blank">直角坐标</a> <a href="/tags/4/" title="测试" class="c1" target="_blank">测试</a> <a href="/tags/51/" title="试题" class="c1" target="_blank">试题</a> <a href="/tags/55/" title="数学" class="c1" target="_blank">数学</a> <a href="/tags/180/" title="直角" class="c1" target="_blank">直角</a> <a href="/tags/453/" title="平面" class="c1" target="_blank">平面</a> <a href="/tags/873/" title="直角坐标" class="c1" target="_blank">直角坐标</a> <a href="/tags/4/" title="测试" class="c1" target="_blank">测试</a> <a href="/tags/51/" title="试题" class="c1" target="_blank">试题</a> <a href="/tags/55/" title="数学" class="c1" target="_blank">数学</a> <a href="/tags/180/" title="直角" class="c1" target="_blank">直角</a> <a href="/tags/453/" title="平面" class="c1" target="_blank">平面</a> <a href="/tags/873/" title="直角坐标" class="c1" target="_blank">直角坐标</a> (三角形②与三角形③关于轴对称);

三角形①的顶点坐标为 <a href="/tags/4/" title="测试" class="c1" target="_blank">测试</a> <a href="/tags/51/" title="试题" class="c1" target="_blank">试题</a> <a href="/tags/55/" title="数学" class="c1" target="_blank">数学</a> <a href="/tags/180/" title="直角" class="c1" target="_blank">直角</a> <a href="/tags/453/" title="平面" class="c1" target="_blank">平面</a> <a href="/tags/873/" title="直角坐标" class="c1" target="_blank">直角坐标</a> <a href="/tags/4/" title="测试" class="c1" target="_blank">测试</a> <a href="/tags/51/" title="试题" class="c1" target="_blank">试题</a> <a href="/tags/55/" title="数学" class="c1" target="_blank">数学</a> <a href="/tags/180/" title="直角" class="c1" target="_blank">直角</a> <a href="/tags/453/" title="平面" class="c1" target="_blank">平面</a> <a href="/tags/873/" title="直角坐标" class="c1" target="_blank">直角坐标</a>  <a href="/tags/4/" title="测试" class="c1" target="_blank">测试</a> <a href="/tags/51/" title="试题" class="c1" target="_blank">试题</a> <a href="/tags/55/" title="数学" class="c1" target="_blank">数学</a> <a href="/tags/180/" title="直角" class="c1" target="_blank">直角</a> <a href="/tags/453/" title="平面" class="c1" target="_blank">平面</a> <a href="/tags/873/" title="直角坐标" class="c1" target="_blank">直角坐标</a> <a href="/tags/4/" title="测试" class="c1" target="_blank">测试</a> <a href="/tags/51/" title="试题" class="c1" target="_blank">试题</a> <a href="/tags/55/" title="数学" class="c1" target="_blank">数学</a> <a href="/tags/180/" title="直角" class="c1" target="_blank">直角</a> <a href="/tags/453/" title="平面" class="c1" target="_blank">平面</a> <a href="/tags/873/" title="直角坐标" class="c1" target="_blank">直角坐标</a> (三角形③与三角形①关于原点对称).




3